Giai đoạn 1:

`300\text{ K} -> 368,6\text{ K}`

`\Delta S_1 = 14,964 \cdot \ln(\frac{368,6}{300}) + 26,08 \cdot 10^{-3} \cdot (368,6 - 300)`

`\Delta S_1 = 14,964 \cdot 0,205937 + 26,08 \cdot 10^{-3} \cdot 68,6 ~~ 4,87073 \text{ J/(K}\cdot\text{mol)}`

Giai đoạn 2:

`S_{\text{rombic}} -> S_{\text{đơn tà}}`

`\Delta S_2 = \frac{296,78}{368,6} ~~ 0,80515 \text{ J/(K}\cdot\text{mol)}`

Giai đoạn 3:

`368,6\text{ K} ->400\text{ K}`

`\Delta S_3 = 14,88 \cdot \ln(\frac{400}{368,6}) + 29,09 \cdot 10^{-3} \cdot (400 - 368,6)`

`\Delta S_3 = 14,88 \cdot 0,081736 + 29,09 \cdot 10^{-3} \cdot 31,4 ~~ 2,12966 \text{ J/(K}\cdot\text{mol)}`

Tổng biến thiên entropi:

`\Delta S_m = \Delta S_1 + \Delta S_2 + \Delta S_3 = 4,87073 + 0,80515 + 2,12966 ~~ 7,80554 \text{ J/(K}\cdot\text{mol)}`

Biến thiên entropi cho `100\text{ g}` lưu huỳnh:

`\Delta S = n \cdot \Delta S_m = 3,125 \cdot 7,80554 = 24,39 \text{ J/K}`