

B1: phân tích đa thức thành nhân tử
a) x^2-4xy-5y^2
b) (x-1)^3-1
c) x^3-3x^2+3x-2
d) x^3-3x^2+3x+7
e) 2x^3-3x^2+3x-1
B2: phân tích đa thức thành nhân tử
a) x^6-y^4
b) x^3-8
c) x^7+1
d) x^10-1
e) x^6+216
f) 27x^3+125x^3
g)8x^3-y^3-6xy(2x-y)
h) 9(x-5y)^2-16(x+y)^2
i) (3x+2)^2-2(x-1)(3x+2)+(x-1)^2
Làm giúp mình vs mình đang cần gấp, mính chép trong đề được giao nếu sai đề bài chỗ nào thì các bạn sửa lại giúp mình nha
Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
Bài `1:`
`a) x^2 - 4xy - 5y^2`
` = x^2 + xy - 5xy - 5y^2`
` = x(x + y) - 5y(x + y) = (x + y)(x - 5y)`
`b) (x - 1)^3 - 1`
` = (x - 1)^3 - 1^3`
` = (x - 1 - 1)[ (x - 1)^2 + 1 . (x - 1) + 1^2]`
` = (x - 2)(x^2 - 2x + 1 + x - 1 + 1)`
` = (x - 2)(x^2 - x + 1)`
`c) x^3 - 3x^2 + 3x - 2`
` = (x^3 - 3x^2 + 3x - 1) - 1`
` = (x - 1)^3 - 1 = (x - 2)(x^2 - x + 1)` (đã chứng minh ở câu `b`)
`d) x^3 - 3x^2 + 3x + 7`
` = x^3 - 3x^2 + 3x - 1 + 8`
` = (x - 1)^3 + 8 = (x - 1)^3 + 2^3`
` = (x - 1 + 2)[ (x - 1)^2 - 2(x - 1) + 2^2]`
` = (x + 1)(x^2 - 2x + 1 - 2x + 2 + 4)`
` = (x + 1)(x^2 - 4x + 7)`
`e) 2x^3 - 3x^2 + 3x - 1`
` = x^3 + (x^3 - 3x^2 + 3x - 1)`
` = x^3 + (x - 1)^3`
` = (x + x - 1)[ x^2 - x(x - 1) + (x - 1)^2]`
` = (2x - 1)(x^2 - x^2 + x + x^2 - 2x + 1)`
` = (2x - 1)(x^2 - x + 1)`
Bài `2:`
`a) x^6 - y^4`
` = (x^3)^2 - (y^2)^2`
` = (x^3 - y^2)(x^3 + y^2)`
`b) x^3 - 8 = x^3 - 2^3`
` = (x - 2)(x^2 + 2x + 4)`
`c) x^7 + 1`
` = x^7 + 1^7`
` = (x + 1)(x^6 - x^5 + x^4 - x^3 + x^2 - x + 1)`
`d) x^10 - 1`
` = x^10 - 1^10`
` = (x - 1)(x^9 + x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x + 1)`
`e) x^6 + 216`
` = (x^2)^3 + 6^3`
` = (x^2 + 6)(x^4 - 6x^2 + 36)`
`f) 27x^3 + 125y^3` (Chắc đề sai)
` = (3x)^3 + (5y)^3`
` = (3x + 5y)(9x^2 - 15xy + 25y^2)`
`g) 8x^3 - y^3 - 6xy(2x - y)`
` = (2x)^3 - 3 . (2x)^2 . y + 3 . x . y^2 - y^3`
` = (2x -y)^3`
`h) 9(x - 5y)^2 - 16(x + y)^2`
` = [ 3(x - 5y)]^2 - [ 4(x + y)]^2`
` = [ 3(x - 5y) - 4(x + y)][ 3(x - 5y) + 4(x + y)]`
` = (-x-19y)(7x-11y)`
`i) (3x + 2)^2 - 2(x - 1)(3x + 2) + (x - 1)^2`
` = [ (3x + 2) - (x - 1)]^2`
` = (3x + 2 - x + 1)^2 = (2x + 3)^2`
Hãy giúp mọi người biết câu trả lời này thế nào?

` @ MathGenius @ `
` 1 // `
` a) x^2 - 4xy - 5y^2 `
` = x^2 + xy - 5xy - 5y^2 `
` = x ( x + y ) - 5y ( x + y ) `
` = ( x + y ) ( x - 5y ) `
` b) ( x - 1 )^3 - 1 `
` = ( x - 1 )^3 - 1^3 `
` = [ ( x - 1 ) - 1 ] [ ( x - 1 )^2 + ( x - 1 ) * 1 + 1 ] `
` = ( x - 2 ) ( x^2 - 2x + 1 + x - 1 + 1 ) `
` = ( x - 2 ) ( x^2 - x + 1 ) `
` c) x^3 - 3x^2 + 3x - 2 `
` = x^3 - 3x^2 + 3x - 1 - 1 `
` = ( x^3 - 3x^2 + 3x - 1 ) - 1 `
` = ( x - 1 )^3 - 1 `
` = ( x - 1 )^3 - 1^3 `
` = [ ( x - 1 ) - 1 ] [ ( x - 1 )^2 + ( x - 1 ) * 1 + 1 ] `
` = ( x - 2 ) ( x^2 - 2x + 1 + x - 1 + 1 ) `
` = ( x - 2 ) ( x^2 - x + 1 ) `
` d) x^3 - 3x^2 + 3x + 7 `
` = x^3 - 3x^2 + 3x - 1 + 8 `
` = ( x^3 - 3x^2 + 3x - 1 ) + 8 `
` = ( x - 1 )^3 + 2^3 `
` = ( x - 1 + 2 ) [ ( x - 1 )^2 - 2 ( x - 1 ) + 4 ] `
` = ( x + 1 ) ( x^2 - 2x + 1 - 2x + 2 + 4 ) `
` = ( x + 1 ) ( x^2 - 4x + 7 ) `
` e) 2x^3 - 3x^2 + 3x - 1 `
` = x^3 + x^3 - 3x^2 + 3x - 1 `
` = x^3 + ( x^3 - 3x^2 + 3x - 1 ) `
` = x^3 + ( x - 1 )^3 `
` = ( x + x - 1 ) [ x^2 - x ( x - 1 ) + ( x - 1 )^2 ] `
` = ( 2x - 1 ) ( x^2 - x^2 + x + x^2 - 2x + 1 ) `
` = ( 2x - 1 ) ( x^2 - x + 1 ) `
` 2 // `
` a) x^6 - y^4 `
` = ( x^3 )^2 - ( y^2 )^2 `
` = ( x^3 - y^2 ) ( x^3 + y^2 ) `
` b) x^3 - 8 `
` = x^3 - 2^3 `
` = ( x - 2 ) ( x^2 + 2x + 4 ) `
` c) x^7 + 1 `
` = ( x + 1 ) ( x^6 - x^5 + x^4 - x^3 + x^2 - x + 1 ) `
` d) x^10 - 1 `
` = ( x^5 )^2 - 1^2 `
` = ( x^5 - 1 ) ( x^5 + 1 ) `
` e) x^6 + 216 `
` = ( x^2 )^3 + 6^3 `
` = ( x^2 + 6 ) ( x^4 - 6x^2 + 36 ) `
` f) 27x^3 + 125x^3 `
` = ( 3x )^3 + ( 5x )^3 `
` = ( 3x + 5x ) ( 9x^2 - 15x^2 + 25x^2 ) `
` = 8x * 19x^2 `
` = 152x^3 `
` g) 8x^3 - y^3 - 6xy ( 2x - y ) `
` = 8x^3 - y^3 - 3 * 2x * y * ( 2x - y ) `
` = ( 2x - y )^3 `
` h) 9 ( x - 5y )^2 - 16 ( x + y )^2 `
` = [ 3 ( x - 5y ) ]^2 - [ 4 ( x + y ) ]^2 `
` = [ 3 ( x - 5y ) - 4 ( x + y ) ] [ ( 3 ( x - 5y ) + 4 ( x + y ) ] `
` = ( 3x - 15y - 4x - 4y ) ( 3x - 15y + 4x + 4y ) `
` = ( - x - 19y ) ( 7x - 11y ) `
` i) ( 3x + 2 )^2 - 2 ( x - 1 ) ( 3x + 2 ) + ( x - 1 )^2 `
` = [ ( 3x + 2 ) - ( x - 1 ) ]^2 `
` = ( 2x + 3 )^2 = ( 2x + 3 ) ( 2x + 3 ) `
Hãy giúp mọi người biết câu trả lời này thế nào?

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