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Điều kiện: `x>0, x≠1.`

`A=(\frac{1}{x-\sqrt{x}}+\frac{1}{\sqrt{x}-1}):\frac{\sqrt{x}+1}{x-2\sqrt{x}+1}`
`= \frac{1+\sqrt{x}}{\sqrt{x}(\sqrt{x}-1)}.\frac{(\sqrt{x}-1)^2}{\sqrt{x}+1}` 
`=\frac{\sqrt{x}-1}{\sqrt{x}}` 

 Vậy `A=\frac{\sqrt{x}-1}{\sqrt{x}}` với `x>0, x≠1.`

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