Giải giúp mình bài tìm x

`a)` `x+3/10=7/5`$\\$ $\quad x\qquad\quad=\dfrac{7}{5}-\dfrac{3}{10}\\\quad x\qquad\quad=\dfrac{11}{10}$$\\$`b)` `(-7)/8=14/x`$\\$ $-7\times x=8\times14$$\\$ `-7\times x=112`$\\$ $\qquad\,\,\,\,x=\dfrac{112}{-7}\\\qquad\,\,\,\,x=-16$$\\$$c)\,\dfrac{4}{-9}:x=\dfrac{-5}{-3}\\\quad\qquad\,\,\, x=\dfrac{4}{-9}:\dfrac{-5}{-3}\\\,\,\,\qquad \quad x=\dfrac{-4}{15}$$\\$ $d)\, x:\dfrac{-2}{11}-\dfrac{5}{8}=\dfrac{-5}{-3}\\\quad x:\dfrac{-2}{11}\qquad\,=\dfrac{-5}{-3}+\dfrac{5}{8}\\\quad x:\dfrac{-2}{11}\qquad\,=\dfrac{55}{24}\\\quad x\qquad\qquad\,\,\,\;=\dfrac{55}{24}\times\dfrac{-2}{11}\\\quad x\qquad\qquad\,\,\,\;=\dfrac{-5}{12}$$\\$$e)\,x\times\Bigg(\dfrac{-2}{5}+\dfrac{8}{15}\Bigg)=\dfrac{-3}{35}\\\quad x\times\dfrac{2}{15}=\dfrac{-3}{35}\\\quad x\qquad\,\,\,\,=\dfrac{-3}{35}:\dfrac{2}{15}\\\quad x\qquad\,\,\,\,=\dfrac{-9}{14}$