a) (7/2+2x):3/14=7/12
b)(1/2x-3/4)^2-1/4=2
d)x+1/2022+x+2/2021+x+3/2020=-3
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nếu câu trả lời hữu ích nhé!
Đáp án + giải thích các bước giải:
`a)` `(7/2+2x):3/14=7/12`
`7/2+2x=7/12*3/14`
`7/2+2x=1/8`
`2x=1/8-7/2`
`2x=-27/8`
`x=-27/8:2`
`x=-27/16`
Vậy `x=-27/16`.
`b)` `(1/2x-3/4)^2-1/4=2`
`(1/2x-3/4)^2=2+1/4`
`(1/2x-3/4)^2=9/4`
Trường hợp `1`.
`(1/2x-3/4)^2=(3/2)^2`
`1/2x-3/4=3/2`
`1/2x=3/2+3/4`
`1/2x=9/4`
`x=9/4:1/2`
`x=9/2`.
Trường hợp `2`.
`(1/2x-3/4)^2=(-3/2)^2`
`1/2x-3/4=-3/2`
`1/2x=-3/2+3/4`
`1/2x=-3/4`
`x=-3/4:1/2`
`x=-3/2`.
Vậy `x in{9/2;-3/2}`.
`d)` `(x+1)/2022+(x+2)/2021+(x+3)/2020=-3`
`((x+1)/2022+1)+((x+2)/2021+1)+((x+3)/2020+1)=-3+3`
`((x+1)/2022+2022/2022)+((x+2)/2021+2021/2021)+((x+3)/2020+2020/2020)=0`
`(x+2023)/2022+(x+2023)/2021+(x+2023)/2020=0`
`(x+2023)(1/2022+1/2021+1/2020)=0`
Vì `(1/2022+1/2021+1/2020)ne0`
Nên `x+2023=0`
`x=-2023`
Vậy `x=-2023`.
Hãy giúp mọi người biết câu trả lời này thế nào?
`a)(7/2+2x):3/14=7/12`
`7/2+2x=7/12.3/14`
`7/2+2x=1/8`
`2x=1/8-7/2`
`2x=-27/8`
`x=-27/8:2`
`x=-27/16`
Vậy `x=-27/16`.
`b)(1/2x-3/4)^2-1/4=2`
`(1/2x-3/4)^2=2+1/4`
`(1/2x-3/4)^2=9/4`
`TH_1`.
`(1/2x-3/4)^2=(3/2)^2`
`1/2x-3/4=3/2`
`1/2x=3/2+3/4`
`1/2x=9/4`
`x=9/4:1/2`
`x=9/2`.
`TH_2`.
`(1/2x-3/4)^2=(-3/2)^2`
`1/2x-3/4=-3/2`
`1/2x=-3/2+3/4`
`1/2x=-3/4`
`x=-3/4:1/2`
`x=-3/2`.
Vậy `x in{9/2;-3/2}`.
`d)(x+1)/2022+(x+2)/2021+(x+3)/2020=-3`
`((x+1)/2022+1)+((x+2)/2021+1)+((x+3)/2020+1)=-3+3`
`((x+1)/2022+2022/2022)+((x+2)/2021+2021/2021)+((x+3)/2020+2020/2020)=0`
`(x+2023)/2022+(x+2023)/2021+(x+2023)/2020=0`
`(x+2023)(1/2022+1/2021+1/2020)=0`
Do `(1/2022+1/2021+1/2020)ne0`
`->x+2023=0`
`x=-2023`
Vậy `x=-2023`.
$#ptjuoy$
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