Đáp án:

a) Sai

b) Sai

c) Sai

d) Sai

Giải thích các bước giải:

a) Áp suất pittong gây ra cho khí trong xi lanh là:

\(p = \dfrac{{mg}}{S} = \dfrac{{0,8.10}}{{{{40.10}^{ - 4}}}} = 2000Pa\)

b) Ta có: 

\(\begin{array}{l}
{p_1}{V_1} = {p_2}{V_2} \Rightarrow {p_1}.25,5 = \left( {{p_1} + 2000} \right).25\\
 \Rightarrow {p_1} = 100000Pa
\end{array}\)

c) Ta có: 

\(\begin{array}{l}
{p_1}{V_1} = {p_1}'{V_1}'\\
 \Rightarrow 100000.25,5 = {p_1}'.25,25\\
 \Rightarrow {p_1}' = \dfrac{{102}}{{101}}{.10^5}\left( {Pa} \right)\\
\dfrac{{{p_1}'}}{{{T_1}}} = \dfrac{{{p_2}'}}{{{T_2}}} \Rightarrow \dfrac{{\dfrac{{102}}{{101}}{{.10}^5}}}{{27 + 273}} = \dfrac{{\dfrac{{102}}{{101}}{{.10}^5} + 2000}}{{{T_2}}}\\
 \Rightarrow {T_2} = 300,02K\\
 \Rightarrow {t_2} = 27,{02^o}C
\end{array}\)

d) Ta có: 

\(\begin{array}{l}
\dfrac{{{p_2}{V_2}}}{{{T_2}}} = \dfrac{{{p_2}'{V_2}'}}{{{T_2}'}}\\
 \Rightarrow \dfrac{{\left( {100000 + 2000} \right).25}}{{27 + 273}} = \dfrac{{{p_2}'.\left( {25 + \Delta h} \right)}}{{50 + 273}}\\
 \Rightarrow {p_2}'.\left( {25 + \Delta h} \right) = 2745500\\
\dfrac{{\left( {{p_2}' - 2000} \right){V_1}'}}{{{T_1}}} = \dfrac{{{p_2}'{V_2}'}}{{{T_2}'}}\\
 \Rightarrow \dfrac{{\left( {{p_2}' - 2000} \right)\left( {25,5 - \Delta h} \right)}}{{27 + 273}} = \dfrac{{{p_2}'.\left( {25 + \Delta h} \right)}}{{50 + 273}}\\
 \Rightarrow \dfrac{{\left( {{p_2}' - 2000} \right)\left( {25,5 - \Delta h} \right)}}{{300}} = \dfrac{{2745500}}{{50 + 273}} = 8500\\
 \Rightarrow \left( {{p_2}' - 2000} \right)\left( {25,5 - \Delta h} \right) = 2550000\\
 \Rightarrow \left( {\dfrac{{2745500}}{{25 + \Delta h}} - 2000} \right)\left( {25,5 - \Delta h} \right) = 2550000\\
 \Rightarrow \Delta h = 0,94cm
\end{array}\)