`(2x+1)(y-2)=12`

`=>` `(y-2)=12` `\vdots` `(2x+1)`

`=>` `(y-2)=(2x+1) in Ư_(12)={+-1;+-2;+-3;+-4;+-6;+-12}`

Vì `2x+1` là số lẻ nên :

`(2x+1) in {+-1;+-3}`

`=>` `2x in {0;-2;-4;2}`

`=>` `x in {0;-1;-2;1}`

Suy ra : `y-2 in {0;-12;-6;12}`

`=>` `y in {2;-10;-4;14}`

Vậy `x in {0;+-1;-2}` 

       `y in {-10;-4;1;14}`