4)
√3−√5(√10−√2)(3+√5)
=√6−2√5(√5−1)(3+√5)
=(6−2√5)(3+√5)
=18+6√5−6√5−20
=−2
6)
(4−√15)(√6+√10)+√4+√15
=(4−√15)(√5+√3)√8+2√15
=(4−√15)(√5+√3)(√5+√3)
=(4−√15)(8+2√15)
=32−8√15+8√15−30
=2
8)
(√6+√2)(4−2√3)√2+√3
=(√3+1).√4+2√3(4−2√3)
=(√3+1)2.(4−2√3)
=(4+2√3)(4−2√3)
=16−12
=4.