Giúp vs ahhhhhhhhhhh

Giải thích các bước giải:

a.Ta có: $\widehat{ADK}=\widehat{DKE}(=80^o)$

               $\widehat{ADK},\widehat{DKE}$ so le trong

$\to AB//KE$

b.Vì $AB//KE\to \widehat{ACL}=\widehat{KEL}=60^o$(đồng vị)

$\to \widehat{LCB}=180^o-\widehat{ACL}=120^o$

c.Ta có: $\widehat{GKE}=180^o-\widehat{DKE}=100^o=\widehat{SGO}$

$\to KE//GO$

$\to \widehat{OCB}+\widehat{CON}=180^o$

Ta có:

$\widehat{HOE}=90^o-\widehat{HCO}=\dfrac12(180^o-2\widehat{HCO})=\dfrac12(180^o-\widehat{OCB})=\dfrac12\widehat{EON}$

$\to OH$ là phân giác $\widehat{EON}$