`(3x−5)(2−x)≤0`

`<=>`$\left[\begin{matrix} \begin{cases} 3x−5≥0\\2−x≤0 \end{cases}\\ \begin{cases} 3x−5≤0\\2−x≥0 \end{cases}\end{matrix}\right.$

`<=>`$\left[\begin{matrix} \begin{cases} x≥\frac{5}{3}\\x≥2 \end{cases}\\ \begin{cases} x≤\frac{5}{3}\\x≤2 \end{cases}\end{matrix}\right.$`=>{(x≥2),(x≤\frac{5}{3}):}`

Vậy `x in (-oo,5/3]uu[2,+oo)`