Mn giúp mo phần B2 , C2 kia đi :,((((

Đáp án:

Bài `5`:

`b) (7(2-x))/6 - 2 \ge (2(x-1))/3`

`=> (14 - 7x)/6 - 2 \ge (2x - 2)/3`

`=> (14-7x-12)/6 \ge (4x-4)/6`

`=> (2 - 7x)/6 \ge (4x - 4)/6`

`=> 2 - 7x \ge 4x - 4`

`=> -7x - 4x \ge -4 - 2`

`=> -11x \ge -6`

`=> x \le 6/11`

 Vậy `S = { x | x \le 6/11}`

`c) (2x - 2)/5 + 3/10 < (x - 2)/4`

`=> (4x - 4 + 3)/10 < (x - 2)/4`

`=> (4x - 1)/10 < (x - 2)/4`

`=> ( 2(4x-1))/20 < ( 5(x-2))/20`

`=> 8x-2 < 5x - 10`

`=> 8x - 5x < -10 + 2`

`=> 3x < -8`

`=> x < -8/3`

Vậy `S = { x | x < -8/3}`