Giúp e bài 9 10 vs ạaaaaa

`9)`

Luôn có `M_{CO}<M_A<M_{CO_2}`

`->28<M_A<44`

`->14<{M_A}/2<22`

`->14<d_{A//H_2}<22`

`10)`

`M_{hh}=5.2=10(g//mol)`

`->{n_{H_2}}/{n_{CO_2}}={44-10}/{10-2}=4,25`

Đặt `n_{CO_2}=1(mol)->n_{H_2}=4,25(mol)`

`\%V_{CO_2}=1/{1+4,25}.100\%=19,05\%`

`\%V_{H_2}=100-19,05=80,95\%`

`\%m_{CO_2}={1.44}/{1.44+4,25.2}.100\%=83,81\%`

`\%m_{H_2}=100-83,81=16,19\%`