(x-2/3)^2=1/9 Giúp e ạ em cơn

`(x-2/3)^2=1/9`

`=>(x-2/3)^2=(+-1/3)^2`

`=>`\(\left[ \begin{array}{l}x-\dfrac{2}{3}=\dfrac{1}{3}\\x-\dfrac{2}{3}=-\dfrac{1}{3}\end{array} \right.\) 

`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}+\dfrac{2}{3}\\x=-\dfrac{1}{3}+\dfrac{2}{3}\end{array} \right.\) 

`=>`\(\left[ \begin{array}{l}x=1\\x=\dfrac{1}{3}\end{array} \right.\) 

Vậy `x=1;x=1/3`