Mn giúp mình với ạ!!!

`#Zi`

Đáp án:

Giải thích các bước giải:

$a)2\sqrt{3}(\sqrt{2}-3)+(\sqrt{2}-\sqrt{3})^2+6\sqrt{3}$

$=2\sqrt{6}-6\sqrt{3}+2-2\sqrt{6}+3+6\sqrt{3}$

$=-6\sqrt{3}+2+3+6\sqrt{3}$

`=2+3`

`=5`

~~~~~~~~~~~~~~~~~~~~~~~~

$b)2\sqrt{40\sqrt{12}}-2\sqrt{\sqrt{75}}-3\sqrt{5\sqrt{48}}$

$=2\sqrt{80\sqrt{3}}-2\sqrt[4]{75}-3\sqrt{20\sqrt{3}}$

$=2.4\sqrt{5\sqrt{3}}-2\sqrt[4]{75}-3.2\sqrt{5\sqrt{3}}$

$=8\sqrt{5\sqrt{3}}-2\sqrt[4]{75}-6\sqrt{5\sqrt{3}}$

$=8\sqrt{\sqrt{5^2}\sqrt{3}}-2\sqrt[4]{75}-6\sqrt{\sqrt{5^2}\sqrt{3}}$

$=8\sqrt{\sqrt{5^2.3}}-2\sqrt[4]{75}-6\sqrt{\sqrt{5^2.3}}$

$=8\sqrt{\sqrt{25.3}}-2\sqrt[4]{75}-6\sqrt{\sqrt{25.3}}$

$=8\sqrt{\sqrt{75}}-2\sqrt[4]{75}-6\sqrt{\sqrt{75}}$

$=8\sqrt[4]{75}-2\sqrt[4]{75}-6\sqrt[4]{75}$

`=0`