rút gọn: căn x /căn x -3 +2 cănx -24/ x-9

Đáp án:

$\dfrac{\sqrt{x}}{\sqrt{x}-3}+\dfrac{2\sqrt{x}-24}{x-9}=\dfrac{\sqrt{x}+8}{\sqrt{x}+3}$

Giải thích các bước giải:

$\dfrac{\sqrt{x}}{\sqrt{x}-3}+\dfrac{2\sqrt{x}-24}{x-9}\,\,\,(x\ge0;x\ne9)\\=\dfrac{\sqrt{x}}{\sqrt{x}-3}+\dfrac{2\sqrt{x}-24}{(\sqrt{x}-3)(\sqrt{x}+3)}\\=\dfrac{\sqrt{x}(\sqrt{x}+3)+2\sqrt{x}-24}{(\sqrt{x}-3)(\sqrt{x}+3)}\\=\dfrac{x+3\sqrt{x}+2\sqrt{x}-24}{(\sqrt{x}-3)(\sqrt{x}+3)}\\=\dfrac{x+5\sqrt{x}-24}{(\sqrt{x}-3)(\sqrt{x}+3)}\\=\dfrac{(\sqrt{x}-3)(\sqrt{x}+8)}{(\sqrt{x}-3)(\sqrt{x}+3)}\\=\dfrac{\sqrt{x}+8}{\sqrt{x}+3}$