giúp mk với ạ ;-;;;;;;;;;;;;;

Đáp án:

$S=\left\{\dfrac{197}{11}\right\}$

Giải thích các bước giải:

$\dfrac{3(x-11)}{4}=\dfrac{3(x+1)}{5}-\dfrac{2(2x-5)}{10}\\⇔\dfrac{3x-33}{4}-\dfrac{3x+3}{5}+\dfrac{4x-10}{10}=0\\⇔\dfrac{5(3x-33)}{20}-\dfrac{4(3x+3)}{20}+\dfrac{2(4x-10)}{20}=0\\⇔\dfrac{15x-165-12x-12+8x-20}{20}=0\\⇔11x-197=0\\⇔x=\dfrac{197}{11}$

Vậy $S=\left\{\dfrac{197}{11}\right\}$