Giúp em câu 23-24-25 với ạ

Câu 23: A

Áp dụng phương trình đẳng nhiệt:

\(\begin{array}{l}
{p_1}{V_1} = n{p_2}{V_2}\\
 \Rightarrow 2,{75.10^6}{.6.10^{ - 3}} = n{.10^5}.3,{3.10^{ - 3}}\\
 \Rightarrow n = 50
\end{array}\)

Câu 24: B

Ta có: 

\(\begin{array}{l}
{p_0}{V_0} = \left( {{p_0} + {{2.10}^5}} \right)\left( {{V_0} - 3} \right)\\
 \Rightarrow {p_0}{V_0} = {p_0}{V_0} - 3{p_0} + {2.10^5}.{V_0} - {6.10^5}\\
 \Rightarrow  - 3{p_0} + {2.10^5}.{V_0} = {6.10^5}\\
{p_0}{V_0} = \left( {{p_0} + {{5.10}^5}} \right)\left( {{V_0} - 5} \right)\\
 \Rightarrow {p_0}{V_0} = {p_0}{V_0} - 5{p_0} + {5.10^5}.{V_0} - {25.10^5}\\
 \Rightarrow  - 5{p_0} + {5.10^5}.{V_0} = {25.10^5}\\
 \Rightarrow \left\{ \begin{array}{l}
{p_0} = {4.10^5}Pa\\
{V_0} = 9l
\end{array} \right.
\end{array}\)

Câu 25: B

Ta có: 

\(\begin{array}{l}
{p_1}{V_1} = {p_2}{V_2}\\
 \Rightarrow 1.2,4 = 0,5{V_2}\\
 \Rightarrow {V_2} = 4,8{m^3}
\end{array}\)