giải hộ em nha mọi người

Giải thích các bước giải:

$\left\{ \begin{array}{l}(1+\sqrt{2})x+(1-\sqrt{2})y=5\\(1+\sqrt{2})x+(1+\sqrt{2})y=3\end{array} \right.$

$⇔\left\{ \begin{array}{l}-2\sqrt{2}y=2\\(1+\sqrt{2})x+(1-\sqrt{2})y=5\end{array} \right.$
$⇔\left\{ \begin{array}{l}y=-\dfrac{\sqrt{2}}{2}\\(1+\sqrt{2})x+(1-\sqrt{2})(-\dfrac{\sqrt{2}}{2})=5\end{array} \right.$

$⇔\left\{ \begin{array}{l}y=-\dfrac{\sqrt{2}}{2}\\(1+\sqrt{2})x-\dfrac{2-\sqrt{2}}{2}=5\end{array} \right.$
$⇔\left\{\begin{array}{l}(1+\sqrt{2})x=\dfrac{8+\sqrt{2}}{2}\\y=-\dfrac{\sqrt{2}}{2}\end{array} \right.$

$⇔\left\{ \begin{array}{l}x=\dfrac{7\sqrt{2}-6}{2}\\y=-\dfrac{\sqrt{2}}{2}\end{array} \right.$

Vậy $(x;y)=(\dfrac{7\sqrt{2}-6}{2};-\dfrac{\sqrt{2}}{2})$