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`(sin^2 30^o + cos^2 60^o)/(tan^2025 45^o) - (sqrt{2})/2` ` = ( (1/2)^2 + (1/2)^2)/(1^2025) - (sqrt{2})/2` ` = (1/4 + 1/4)/1 - (sqrt{2})/2` ` = 1/2 - (sqrt{2})/2 = (1 - sqrt{2})/2`

Đáp án: `(sin^2 (30^o)+cos^2 (60^o))/(tan^(2025) (45^o)) -(sqrt{2})/2` `=((1/2)^2+(1/2)^2)/(1^(2025)) -(sqrt{2})/2` `=(1/4+1/4) -(sqrt{2})/2` `= 1/2 -(sqrt{2})/2` `=(1-sqrt{2})/2` __ `sin30^o=1/2` `cos60^o=1/2` `tan45^o=1`