9
3)
32
+
€0.0 0.0 0.0
=
20
27
Bài 5: Tìm x biết:
4
27
2)

Question

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208wEmilia · Answer

Bài `5:`
`a) (1/3)^(x + 3) + (1/3)^(x + 2) = 4/27`
`to (1/3)^(x + 2) . 1/3 + (1/3)^(x + 2) = 4/27`
`to (1/3)^(x + 2). (1 + 1/3) = 4/27`
`to (1/3)^(x + 2) . 4/3 = 4/27`
`to (1/3)^(x + 2) = 1/9`
`to (1/3)^(x + 2) = (1/3)^2`
`to x + 2 = 2`
`to x = 0`
Vậy `x = 0`
`2) (1/2)^(x + 4) + (1/2)^(x + 1) = 9/32`
`to (1/2)^(x + 1) . (1/2)^3 + (1/2)^(x + 1) = 9/32`
`to (1/2)^(x + 1) . 1/8 + (1/2)^(x + 1) = 9/32`
`to (1/2)^(x + 1) . (1 + 1/8) = 9/32`
`to (1/2)^(x + 1) . 9/8 = 9/32`
`to (1/2)^(x + 1) = 1/4`
`to (1/2)^(x + 1) = (1/2)^2`
`to x +1 = 2`
`to x =1`
Vậy `x = 1`
`3) (2/3)^(x + 2) + (2/3)^(x + 1) = 20/27`
`to (2/3)^(x + 1) . 2/3 + (2/3)^(x + 1) = 20/27`
`to (2/3)^(x + 1) . (2/3 + 1) = 20/27`
`to (2/3)^(x + 1) . 5/3 = 20/27`
`to (2/3)^(x + 1) = 4/9`
`to (2/3)^(x + 1) = (2/3)^2`
`to x + 1 = 2`
`to x = 1`
Vậy `x = 1`

11502369 · Answer

`1)`
`(1/3)^{x+3}+(1/3)^{x+2}=4/27`
`->(1/3)^{x+2} . 1/3+(1/3)^{x+2}=4/27`
`->(1/3)^{x+2}.(1/3+1)=4/27`
`->(1/3)^{x+2} . 4/3=4/27`
`->(1/3)^{x+2}=4/27:4/3`
`->(1/3)^{x+2}=4/27 . 3/4`
`->(1/3)^{x+2}=1/9`
`->(1/3)^{x+2}=(1/3)^{2}`
`->x+2=2`
`->x=0`
Vậy `x=0`
``   
`2)`
`(1/2)^{x+4}+(1/2)^{x+1}=9/32`
`->(1/2)^{x+1}.(1/2)^{3}+(1/2)^{x+1}=9/32`
`->(1/2)^{x+1}. 1/8+(1/2)^{x+1}=9/32`
`->(1/2)^{x+1}.(1/8+1)=9/32`
`->(1/2)^{x+1}. 9/8=9/32`
`->(1/2)^{x+1}=9/32:9/8`
`->(1/2)^{x+1}=1/4`
`->(1/2)^{x+1}=(1/2)^{2}`
`->x+1=2`
`->x=1`
Vậy `x=1`   
``
`3)`
`(2/3)^{x+2}+(2/3)^{x+1}=20/27`
`->(2/3)^{x+1}. 2/3+(2/3)^{x+1}=20/27`
`->(2/3)^{x+1}.(2/3+1)=20/27`
`->(2/3)^{x+1}. 5/3=20/27`
`->(2/3)^{x+1}=20/27:5/3`
`->(2/3)^{x+1}=4/9`
`->(2/3)^{x+1}=(2/3)^{2}`
`->x+1=2`
`->x=1`Vậy `x=1`

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