

Làm 5,6,7,8`````````````````````````````````````````````````````````````````````
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`5.`
`sqrt(23+4sqrt(15))`
`=sqrt(20+2.2sqrt(5).sqrt(3)+3)`
`=sqrt((2sqrt(5)+sqrt(3))^2)`
`=|2sqrt(5)+sqrt(3)|`
`=2sqrt(5)+sqrt(3)`
Vậy `sqrt(23+4sqrt(15))=2sqrt(5)+sqrt(3)`
`6.`
`sqrt(16-2sqrt(55))`
`=sqrt(11-2sqrt(11).sqrt(5)+5)`
`=sqrt((sqrt(11)-sqrt(5))^2)`
`=|sqrt(11)-sqrt(5)|`
`=sqrt(11)-sqrt(5)`
Vậy `sqrt(16-2sqrt(55))=sqrt(11)-sqrt(5)`
`7.`
`sqrt(8-2sqrt(12))`
`=sqrt(6-2sqrt(6).sqrt(2)+2)`
`=sqrt((sqrt(6)-sqrt(2))^2)`
`=|sqrt(6)-sqrt(2)|`
`=sqrt(6)-sqrt(2)`
Vậy `sqrt(8-2sqrt(12))=sqrt(6)-sqrt(2)`
`8.`
`sqrt(8+2sqrt(15))`
`=sqrt(5+2sqrt(5).sqrt(3)+3)`
`=sqrt((sqrt(5)+sqrt(3))^2)`
`=|sqrt(5)+sqrt(3)|`
`=sqrt(5)+sqrt(3)`
Vậy `sqrt(8+2sqrt(15))=sqrt(5)+sqrt(3)`
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`5)``\sqrt{23 + 4\sqrt{15}} = \sqrt{23 + 2\sqrt{60}}`
`= \sqrt{(\sqrt{20})^2 + 2\cdot\sqrt{20}\cdot\sqrt{3} + (\sqrt{3})^2}`
`= \sqrt{(\sqrt{20} + \sqrt{3})^2}`
`= |\sqrt{20} + \sqrt{3}|`
`= 2\sqrt{5} + \sqrt{3}`
`6)``\sqrt{16 - 2\sqrt{55}} = \sqrt{(\sqrt{11})^2 - 2\cdot\sqrt{11}\cdot\sqrt{5} + (\sqrt{5})^2}`
`= \sqrt{(\sqrt{11} - \sqrt{5})^2}`
`= |\sqrt{11} - \sqrt{5}|`
`= \sqrt{11} - \sqrt{5}`
`7)``\sqrt{8 - 2\sqrt{12}} = \sqrt{(\sqrt{6})^2 - 2\cdot\sqrt{6}\cdot\sqrt{2} + (\sqrt{2})^2}`
`= \sqrt{(\sqrt{6} - \sqrt{2})^2}`
`= |\sqrt{6} - \sqrt{2}|`
`= \sqrt{6} - \sqrt{2}`
`8)``\sqrt{8 + 2\sqrt{15}} = \sqrt{(\sqrt{5})^2 + 2\cdot\sqrt{5}\cdot\sqrt{3} + (\sqrt{3})^2}`
`= \sqrt{(\sqrt{5} + \sqrt{3})^2}`
`= |\sqrt{5} + \sqrt{3}|`
`= \sqrt{5} + \sqrt{3}`
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