꧁༺༒༻꧂𝔰𝔴𝔞𝔩𝔩𝔬𝔴꧁༺༒༻

`a)`

$\left(-\dfrac{11}{8}\right) \cdot 6,(3) + 6,(3) \cdot \left(\dfrac{-5}{8}\right)$

$= 6,(3) \cdot \left[\left(-\dfrac{11}{8}\right) + \left(-\dfrac{5}{8}\right)\right]$

$=\dfrac{19}{3} \cdot (-2) = -\dfrac{38}{3} = -12\dfrac{2}{3}$

`b)`

$14\dfrac{1}{4} \cdot \dfrac{3}{4} - 2\dfrac{1}{4} : 1,(3)$

$=\dfrac{7}{2} \cdot \dfrac{3}{4} - \dfrac{9}{4} : \dfrac{4}{3} $

$=\dfrac{3}{4} .  \dfrac{5}{4} = \dfrac{15}{16} $