

Rút gọn :
a) A = 4/(√5 - 1) + 2/(1 - √3) - 2/(√3 - √5)
b) B = √2 + 1/√(5+2√6) + 2/√(8 + 2√15)
c) C = [ 24/(√7 + 1) + 4/(3 + √7) - 3/(√7 + 2) ] (4 - √7)
d) D = [ 15/(3 - √3) - 2/(1 - √3) + 3/(√3 - 2) ] . √(28 + 10√3)
Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
`a)`
`A=4/(sqrt(5)-1)+2/(1-sqrt(3))-2/(sqrt(3)-sqrt(5))`
`=(4(sqrt(5)+1))/(5-1)+(2(1+sqrt(3)))/(1-3)-(2(sqrt(3)+sqrt(5)))/(3-5)`
`=(4(sqrt(5)+1))/4+(2(1+sqrt(3)))/(-2)-(2(sqrt(3)+sqrt(5)))/(-2)`
`=sqrt(5)+1-(1+sqrt(3))+(sqrt(3)+sqrt(5))`
`=sqrt(5)+1-1-sqrt(3)+sqrt(3)+sqrt(5)`
`=2sqrt(5)`
Vậy `A=2sqrt(5)`
`b)`
`B=sqrt(2)+1/sqrt(5+2sqrt(6))+2/sqrt(8+2sqrt(15))`
`=sqrt(2)+1/sqrt((sqrt(3)+sqrt(2))^2)+2/sqrt((sqrt(5)+sqrt(3))^2)`
`=sqrt(2)+1/(sqrt(3)+sqrt(2))+2/(sqrt(5)+sqrt(3))`
`=sqrt(2)+(sqrt(3)-sqrt(2))/(3-2)+(2(sqrt(5)-sqrt(3)))/(5-3)`
`=sqrt(2)+sqrt(3)-sqrt(2)+sqrt(5)-sqrt(3)`
`=sqrt(5)`
Vậy `B=sqrt(5)`
`c)`
`C=24/(sqrt(7)+1)+4/(3+sqrt(7))-3/(sqrt(7)+2)`
`=(24(sqrt(7)-1))/(7-1)+(4(3-sqrt(7)))/(9-7)-(3(sqrt(7)-2))/(7-4)`
`=(24(sqrt(7)-1))/6+(4(3-sqrt(7)))/2-(3(sqrt(7)-2))/3`
`=4(sqrt(7)-1)+2(3-sqrt(7))-(sqrt(7)-2)`
`=(4sqrt(7)-4+6-2sqrt(7)-sqrt(7)+2)(4-sqrt(7))`
`=(sqrt(7)+4)(4-sqrt(7))`
`=(4+sqrt(7))(4-sqrt(7))`
`=16-7`
`=9`
Vậy `C=9`
`d)`
`D=[15/(3-sqrt(3))-2/(1-sqrt(3))+3/(sqrt(3)-2)].sqrt(28+10sqrt(3))`
`=[(15(3+sqrt(3)))/(9-3)-(2(1+sqrt(3)))/(1-3)+(3(sqrt(3)+2))/(3-4)].sqrt((5+sqrt(3))^2)`
`=[(15(3+sqrt(3)))/6-(2(1+sqrt(3)))/(-2)+(3(sqrt(3)+2))/(-1)].(5+sqrt(3))`
`=[(5(3+sqrt(3)))/2+(1+sqrt(3))-3(sqrt(3)+2)].(5+sqrt(3))`
`=[(15+5sqrt(3))/2+1+sqrt(3)-3sqrt(3)-6].(5+sqrt(3))`
`=[(15+5sqrt(3))/2-2sqrt(3)-5].(5+sqrt(3))`
`=((15+5sqrt(3)-4sqrt(3)-10)/2).(5+sqrt(3))`
`=((5+sqrt(3))/2).(5+sqrt(3))`
`=(5+sqrt(3))^2/2`
`=(25+10sqrt(3)+3)/2`
`=(28+10sqrt(3))/2`
`=14+5sqrt(3)`
Vậy `D=14+5sqrt(3)`
Hãy giúp mọi người biết câu trả lời này thế nào?
`a) A = 4/(\sqrt{5} - 1) + 2/(1 - \sqrt{3}) - 2/(\sqrt{3} - \sqrt{5})`
`A = 4(\sqrt{5} + 1)/4 + 2(1 + \sqrt{3})/(-2) - 2(\sqrt{3} + \sqrt{5})/(-2)`
`A = (\sqrt{5} + 1) - (1 + \sqrt{3}) + (\sqrt{3} + \sqrt{5})`
`A = \sqrt{5} + 1 - 1 - \sqrt{3} + \sqrt{3} + \sqrt{5}`
`A = 2\sqrt{5}`
`b) B = \sqrt{2} + 1/\sqrt{5 + 2\sqrt{6}} + 2/\sqrt{8 + 2\sqrt{15}}`
`B = \sqrt{2} + 1/(\sqrt{3} + \sqrt{2}) + 2/(\sqrt{5} + \sqrt{3})`
`B = \sqrt{2} + (\sqrt{3} - \sqrt{2})/(3 - 2) + 2(\sqrt{5} - \sqrt{3})/(5 - 3)`
`B = \sqrt{2} + \sqrt{3} - \sqrt{2} + \sqrt{5} - \sqrt{3}`
`B = \sqrt{5}`
`c) C = [ 24/(\sqrt{7} + 1) + 4/(3 + \sqrt{7}) - 3/(\sqrt{7} + 2) ] (4 - \sqrt{7})`
`C = [ 24(\sqrt{7} - 1)/6 + 4(3 - \sqrt{7})/2 - 3(\sqrt{7} - 2)/3 ] (4 - \sqrt{7})`
`C = [ 4(\sqrt{7} - 1) + 2(3 - \sqrt{7}) - (\sqrt{7} - 2) ] (4 - \sqrt{7})`
`C = (4\sqrt{7} - 4 + 6 - 2\sqrt{7} - \sqrt{7} + 2) (4 - \sqrt{7})`
`C = (\sqrt{7} + 4)(4 - \sqrt{7})`
`C = (4 + \sqrt{7})(4 - \sqrt{7})`
`C = 16 - 7`
`C = 9`
`d) D = [ 15/(3 - \sqrt{3}) - 2/(1 - \sqrt{3}) + 3/(\sqrt{3} - 2) ] . \sqrt{28 + 10\sqrt{3}}`
`D = [ 15(3 + \sqrt{3})/6 - 2(1 + \sqrt{3})/(-2) + 3(\sqrt{3} + 2)/(-1) ] . \sqrt{(5 + \sqrt{3})^2}`
`D = [ 5(3 + \sqrt{3})/2 + (1 + \sqrt{3}) - 3(\sqrt{3} + 2) ] . (5 + \sqrt{3})`
`D = [ (15 + 5\sqrt{3})/2 - 2\sqrt{3} - 5 ] . (5 + \sqrt{3})`
`D = [ (15 + 5\sqrt{3} - 4\sqrt{3} - 10)/2 ] . (5 + \sqrt{3})`
`D = [ (5 + \sqrt{3})/2 ] . (5 + \sqrt{3})`
`D = (5 + \sqrt{3})^2 / 2`
`D = (25 + 10\sqrt{3} + 3) / 2`
`D = (28 + 10\sqrt{3}) / 2`
`D = 14 + 5\sqrt{3}`
Hãy giúp mọi người biết câu trả lời này thế nào?
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