

Mn oi giúp em vs còn 4 bài nx
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Đáp án`+`Giải thích các bước giải:
4.
`a)(1/2-x)^3= 1/8-3/4x+3/2x^2-x^3`
`(2x-1)^3= 8x^3-12x^2+6x-1`
`b)(2x-3y)^3= 8x^3-36x^2y+54xy^2-27y^3`
`(0,01-xy)^3= 0,000001-0,0003xy+0,03x^2y^2-x^3y^3`
`c)(1/2+x)^3= 1/8+3/4x+3/2x^2+x^3`
`(2x+1)^3= 8x^3+12x^2+6x+1`
`d)(2x+3y)^3= 8x^3+36x^2y+54xy^2+27y^3`
`(0,01+xy)^3= 0,000001+0,0003xy+0,03x^2y^2+x^3y^3`
`e)(x+1)(x^2-x+1)= x^3+1`
`f)(x-2y)(x^2+2xy+4y^2)= x^3-8y^3`
`g)(x+y+z)^2= x^2+y^2+z^2+2xy+2xz+2yz`
`(x-y+z)^2= x^2+y^2+z^2-2xy+2xz-2yz`
`h)(x-y-z)^2= x^2+y^2+z^2-2xy-2xz+2yz`
5.
`a)(3+xy^2)^2= 9+6xy^2+x^2y^4`
`(2m^2n-10)^2= 4m^4n^2-40m^2n+100`
`b)(a-b^2)(a+b^2)= a^2-b^4`
`c)(a^2+2a+3)(a^2+2a-3)= a^4+4a^3+4a^2-9`
`d)(a^2+2a+3)(a^2-2a-3)= a^4-10a^2-12a-9`
`e)(a^2-2a+3)(a^2+2a-3)= a^4-4a^2+12a-9`
`f)(a^2+2a+3)(a^2-2a+3)= a^4+2a^2+9`
`g)(-a^2-2a+3)(-a^2-2a+3)= a^4+4a^3-2a^2-12a+9`
`h)(a^2+2a)(2a-a^2)= -a^4+4a^2`
Hãy giúp mọi người biết câu trả lời này thế nào?
Bài 4:
`a_1) (1/2 - x)^3`
`= (1/2)^3 - 3 * (1/2)^2 * x + 3 * (1/2) * x^2 - x^3`
`= 1/8 - 3/4 x + 3/2 x^2 - x^3`
`a_2) (2x - 1)^3`
`= (2x)^3 - 3 * (2x)^2 * 1 + 3 * 2x * 1^2 - 1^3`
`= 8x^3 - 12x^2 + 6x - 1`
`b_1) (2x - 3y)^3`
`= (2x)^3 - 3 * (2x)^2 * 3y + 3 * 2x * (3y)^2 - (3y)^3`
`= 8x^3 - 36x^2 y + 54xy^2 - 27y^3`
`b_2) (0,01 - xy)^3`
`= (0,01)^3 - 3 * (0,01)^2 * xy + 3 * 0,01 * (xy)^2 - (xy)^3`
`= 0,000001 - 0,0003xy + 0,03x^2 y^2 - x^3 y^3`
`c_1) (1/2 + x)^3`
`= (1/2)^3 + 3 * (1/2)^2 * x + 3 * (1/2) * x^2 + x^3`
`= 1/8 + 3/4 x + 3/2 x^2 + x^3`
`c_2) (2x + 1)^3`
`= (2x)^3 + 3 * (2x)^2 * 1 + 3 * 2x * 1^2 + 1^3`
`= 8x^3 + 12x^2 + 6x + 1`
`d_1) (2x + 3y)^3`
`= (2x)^3 + 3 * (2x)^2 * 3y + 3 * 2x * (3y)^2 + (3y)^3`
`= 8x^3 + 36x^2 y + 54xy^2 + 27y^3`
`d_2) (0,01 + xy)^3`
`= (0,01)^3 + 3 * (0,01)^2 * xy + 3 * 0,01 * (xy)^2 + (xy)^3`
`= 0,000001 + 0,0003xy + 0,03x^2 y^2 + x^3 y^3`
`e) (x + 1)(x^2 - x + 1) = x^3 + 1^3 = x^3 + 1`
`f) (x - 2y)(x^2 + 2xy + 4y^2)`
`= x^3 - (2y)^3`
`= x^3 - 8y^3`
`g_1) (x + y + z)^2= x^2 + y^2 + z^2 + 2xy + 2yz + 2xz`
`g_2) (x - y + z)^2`
`= [x + (-y) + z]^2`
`= x^2 + (-y)^2 + z^2 + 2 * x * (-y) + 2 * (-y) * z + 2 * x * z`
`= x^2 + y^2 + z^2 - 2xy - 2yz + 2xz`
`h) (x - y - z)^2`
`= [x + (-y) + (-z)]^2`
`= x^2 + (-y)^2 + (-z)^2 + 2 * x * (-y) + 2 * (-y) * (-z) + 2 * x * (-z)`
`= x^2 + y^2 + z^2 - 2xy + 2yz - 2xz`
Bài 5:
`a_1) (3 + xy^2)^2`
`= 3^2 + 2 * 3 * xy^2 + (xy^2)^2`
`= 9 + 6xy^2 + x^2 y^4`
`a_2) (2m^2 n - 10)^2`
`= (2m^2 n)^2 - 2 * (2m^2 n) * 10 + 10^2`
`= 4m^4 n^2 - 40m^2 n + 100`
`b) (a - b^2)(a + b^2) = a^2 - (b^2)^2 = a^2 - b^4`
`c) (a^2 + 2a + 3)(a^2 + 2a - 3)`
`= [(a^2 + 2a) + 3][(a^2 + 2a) - 3]`
`= (a^2 + 2a)^2 - 3^2`
`= (a^2)^2 + 2 * a^2 * 2a + (2a)^2 - 9`
`= a^4 + 4a^3 + 4a^2 - 9`
`d) (a^2 + 2a + 3)(a^2 - 2a - 3)`
`=[a^2 + (2a + 3)][a^2 - (2a + 3)]`
`= (a^2)^2 - (2a + 3)^2`
`= a^4 - [(2a)^2 + 2 * 2a * 3 + 3^2]`
`= a^4 - (4a^2 + 12a + 9)`
`= a^4 - 4a^2 - 12a - 9`
`e) (a^2 - 2a + 3)(a^2 + 2a - 3)`
`= [a^2 - (2a - 3)][a^2 + (2a - 3)]`
`= (a^2)^2 - (2a - 3)^2`
`= a^4 - [(2a)^2 - 2 * 2a * 3 + 3^2]`
`= a^4 - (4a^2 - 12a + 9)`
`= a^4 - 4a^2 + 12a - 9`
`f) (a^2 + 2a + 3)(a^2 - 2a + 3)`
`= [(a^2 + 3) + 2a][(a^2 + 3) - 2a]`
`= (a^2 + 3)^2 - (2a)^2`
`= (a^2)^2 + 2 * a^2 * 3 + 3^2 - 4a^2`
`= a^4 + 6a^2 + 9 - 4a^2`
`= a^4 + 2a^2 + 9`
`g) (-a^2 - 2a + 3)(-a^2 - 2a + 3)`
`= (-a^2 - 2a + 3)^2`
`= [-(a^2 + 2a - 3)]^2`
`= (a^2 + 2a - 3)^2`
`= [(a^2 + 2a) - 3]^2`
`= (a^2 + 2a)^2 - 2 * (a^2 + 2a) * 3 + 3^2`
`= (a^2)^2 + 2 * a^2 * 2a + (2a)^2 - 6a^2 - 12a + 9`
`= a^4 + 4a^3 + 4a^2 - 6a^2 - 12a + 9`
`= a^4 + 4a^3 - 2a^2 - 12a + 9`
`h) (a^2 + 2a)(2a - a^2)`
`= (2a + a^2)(2a - a^2)`
`= (2a)^2 - (a^2)^2`
`= 4a^2 - a^4`
Hãy giúp mọi người biết câu trả lời này thế nào?
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