`color{#42bfb5}\text{H}color{#55c5bc}\text{uy}color{#68ccc4}\text{e}color{#7bd2cb}\text{n}`

Ta có pthh:

`Zn+2HCl to ZnCl_2 + H_2^\uparrow  (1)`

`2Al+6HCl to 2AlCl_3 + 3H_2^\uparrow (2)`

Ta có:

`n_(H_2)=(9,916)/(24,79)=0,4(mol)`

Gọi `n_(Zn)=x(mol)`

`=> m_(Zn)=65x (g)`

Gọi `n_(Al)=y (mol)`

`=> m_(Al)= 27y (mol)`

ta có hệ pt:

$\left \{ {{65x+27y=11,9} \atop {x+3/2y=2/5}} \right.$ 

`=> {(x=0,1),(y=0,2):}`

Kết luận:

`m_(Zn)=65.0,5=6,5(g)`

`=>%m_(Zn)=(6,5)/(11,9).100%=54,62 %`

`=>%m_(Al)=100%-54,62%=45,38%`