`mrmsc?`

`(2x+1/3)(-1/5x -2/3)=0`

`Th1: 2x+1/3=0`

`2x=-1/3`

`x= -1/6`

`Th2: -1/5x - 2/3 = 0`

`-1/5x = 2/3`

`x = -10/3`

Vậy `S = {-1/6;-10/3}`

`x(3x+5)-6x-10=0`

`3x^2+5x-6x-10=0`

`3x^2-x-10=0`

`3x(x-2) + 5(x-2) = 0`

`(3x+5)(x-2)=0`

`th1: 3x+5=0`

`3x=-5`

`x=-5/3`

`th2: x-2=0`

`x=2`

`Vậy S={-5/3;2}`

`(2x-5)^2-9x^2=0`

`(2x-5-3x)(2x-5+3x)=0`

`th1: 2x-5-3x=0`

`-x -5=0`

`-x=5`

`x=-5`

`th2: 2x-5+3x=0`

`5x=5`

`x=1

Vậy `S={-5;1}`

`{3x}/{2x+1} - {4x^2+1}/{4x^2-1} = x/{2x-1}`

`{3x}/{2x+1} - x/{2x-1} = {4x^2+1}/{4x^2-1}`

`3x(2x-1) - x(2x+1) = 4x^2+1`

`6x^2 - 3x - 2x^2 + x -4x^2-1=0`

`-2x=1`

`x=-1/2`

Vậy nghiệm của pt là `x=-1/2`

`{x+3}/{x-3} - {x^2}/{x^2-9} = -6/{x+3}`

`{x+3}/{x-3} + 6/{x+3} = {x^2}/{x^2-9}`

`(x+3)^2 + 6(x-3) = x^2`

`x^2+6x+9+6x-18-x^2=0`

`12x-9=0`

`3(4x-3)=0`

`4x=3`

`x=3/4`

Vậy `...`

`1/{x+1} - x/{x^2-x+1} = {3x}/{x^3+1}`

`(x^2-x+1) - x(x+1) = 3x`

`x^2-x+1-x^2-x-3x=0`

`-5x=-1`

`x=1/5`

Vậy `..`

(có j sai sót thì mai mik sửa nhe)