#juuliétte.

Đáp án:

`Q=(\sqrtx-2)/(3+\sqrtx)+(\sqrtx-3)/(2-\sqrtx)-(9-x)/(x+\sqrtx-6)` `(x ge 0;x ne 4)`

MTC : `(\sqrtx+3)(\sqrtx-2)`

`Q=(\sqrtx-2)/(\sqrtx+3)-(\sqrtx-3)/(\sqrtx-2)-(9-x)/((\sqrtx+3)(\sqrtx-2))`

`Q=((\sqrtx-2)(\sqrtx-2))/((\sqrtx+3)(\sqrtx-2))-((\sqrtx-3)(\sqrtx+3))/((\sqrtx-2)(\sqrtx+3))-(9-x)/((\sqrtx+3)(\sqrtx-2))`

`Q=(x-4\sqrtx+4)/((\sqrtx+3)(\sqrtx-2))-(x-9)/((\sqrtx-2)(\sqrtx+3))-(9-x)/((\sqrtx+3)(\sqrtx-2))`

`Q=(x-4\sqrtx+4-(x-9)-(9-x))/((\sqrtx+3)(\sqrtx-2))`

`Q=(x-4\sqrtx+4-x+9-9+x)/((\sqrtx+3)(\sqrtx-2))`

`Q=(x-4\sqrtx+4)/((\sqrtx+3)(\sqrtx-2))`

`Q=((\sqrtx-2)^2)/((\sqrtx+3)(\sqrtx-2))`

`Q=(\sqrtx-2)/(\sqrtx+3)`