`@` `2` `years ***``\color[#522025][1]``\color[#7c3138][5]``\color[#a5414a][0]``\color[#ce515d][5]`

Đáp án:

`(x+112)/2+(x-115)/215+(x-101)/67+(x+22)/39=0`

`(x+112)/2-6+(x-115)/215+1+(x-101)/67+3+(x+22)/39+2=0`

`(x+112-2*6)/2+(x-115+215)/215+(x-101+67*3)/67+(x+22+2*39)/39=0`

`(x+100)/2+(x+100)/215+(x+100)/67+(x+100)/39=0`

`(x+100)(1/2+1/215+1/67+1/39)=0`

mà `1/2+1/215+1/67+1/39 ne 0`

`to x+100=0`

`to x=-100`

Vậy `x=-100`

``

`(x+2014)/2+(x-11)/2015+(x-76)/975+(x+125)/717=0`

`(7223775(x+2014))/14447550+(7170(x-11))/14447550+(14818(x-76))/14447550+(20150(x+125))/14447550=0`

`to (7223775(x+2014)+7170(x-11)+14818(x-76)+20150(x+125))/14447550=0`

`to 7223775(x+2014)+7170(x-11)+14818(x-76)+20150(x+125)=0`

`to x~~-2002,500795`

 Vậy `x~~-2002,500795`