Bài `2:`

`M=x^3+x^2y-3x^2-xy-y^2+4y+x+2019`

`M=(x^3+x^2y-3x^2)-(xy+y^2-3y)+(x+y-3)+2022`

`M=x^2(x+y-3)-y(x+y-3)+(x+y-3)+2022`

`M=(x+y-3)(x^2-y+1)+2022`

`M=0.(x^2-y+1)+2022`

`M=2022`

Vậy `M=2022`

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