Đáp án:

Giải thích các bước giải:

`4,`

$\left.\begin{array}{l} x^3 - 3x^2 + 2x - 6 \\ x^3 - 3x^2 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2x - 6 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2x - 6 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x - 3 \ \ }{\ \ x^2 + 2 \ \ } \\ \\ \\ \\ \end{array}$

`5,`

$\left.\begin{array}{l} x^3 + 2x^2 - 2x + 3 \\ x^3 + 3x^2 \\ \hline \ \ \ \ \ - x^2 - 2x \\ \ \ \ \ \ - x^2 - 3x \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x + 3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x + 3 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x + 3 \ \ }{\ \ x^2 - x + 1 \ \ } \\ \\ \\ \\ \\ \\ \end{array}$

`6,`

$\left.\begin{array}{l} x^3 - 3x^2 - 4x + 12 \\ x^3 + 2x^2 \\ \hline \ \ \ \ \ - 5x^2 - 4x \\ \ \ \ \ \ - 5x^2 - 10x \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 6x + 12 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 6x + 12 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x + 2 \ \ }{\ \ x^2 - 5x + 6 \ \ } \\ \\ \\ \\ \\ \\ \end{array}$

`7,`

$\left.\begin{array}{l} x^3 + 4x^2 + 3x + 12 \\ x^3 + 4x^2 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x + 12 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x + 12 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x + 4 \ \ }{\ \ x^2 + 3 \ \ } \\ \\ \\ \\ \end{array}$

`8,`

$\left.\begin{array}{l} 2x^3 + 7x^2 + 3x - 2 \\ 2x^3 + 2x^2 \\ \hline \ \ \ \ \ \ \ \ \ \ 5x^2 + 3x \\ \ \ \ \ \ \ \ \ \ \ 5x^2 + 5x \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ - 2x - 2 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ - 2x - 2 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x + 1 \ \ }{\ \ 2x^2 + 5x - 2 \ \ } \\ \\ \\ \\ \\ \\ \end{array}$

`9,`

$\left.\begin{array}{l} x^3 - 2x^2 + 5x - 10 \\ x^3 - 2x^2 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x - 10 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x - 10 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ x - 2 \ \ }{\ \ x^2 + 5 \ \ } \\ \\ \\ \\ \end{array}$

`10,`

$\left.\begin{array}{l} 2x^2 + 3x - 2 \\ 2x^2 - \ \ x \\ \hline \ \ \ \ \ \ \ \ \ \ 4x - 2 \\ \ \ \ \ \ \ \ \ \ \ 4x - 2 \\ \hline \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \end{array}\right|\!\!\!\;\!\!\begin{array}{l} \dfrac{\ \ 2x - 1 \ \ }{\ \ x + 2 \ \ } \\ \\ \\ \\ \end{array}$