Rút gọn phân thức trên

Giúp mik vs

Đáp án`+`Giải thích các bước giải:

`c,``(\frac{2}{x+2} + \frac{2}{x-1}). \frac{x^2-4}{4x^2-1}` `(x\ne1;x\ne-2;x\ne±1/2)`

`=``(\frac{2(x-1)}{(x+2)(x-1)} + \frac{2(x+2)}{(x-1)(x+2)}). \frac{(x+2)(x-2)}{(2x-1)(2x+1)}`

`=(\frac{2x-2}{(x+2)(x-1)}+\frac{2x+4}{(x-1)(x+2)}).\frac{(x+2)(x-2)}{(2x+1)(2x-1)}` 

`=\frac{2x-2+2x+4}{(x-1)(x+2)}.\frac{(x+2)(x-2)}{(2x-1)(2x+1)}` 

`=\frac{4x+2}{(x-1)(x+2)}.\frac{(x+2)(x-2)}{(2x-1)(2x+1)}`

`=\frac{2(2x+1)}{(x-1)(x+2)}.\frac{(x+2)(x-2)}{(2x+1)(2x-1)}`

`=\frac{2}{x-1}.\frac{x-2}{2x-1}`

`=\frac{2(x-2)}{(x-1)(2x-1)}`

`=\frac{2x-4}{2x^2-3x+1}`