Làm giúp mình với, xong mình vote cho 5* và ctlhn nha

`(1)` Tinh bột `->` glucose

`PTHH` `:` `(`$C_{6}$$H_{10}$$O_{5}$`)`$_{n}$ `+` $nH_{2}$`O` `->` $C_{6}$$H_{12}$$O_{6}$

`(2)` glucose `->` ethanol

`PTHH` `:` $C_{6}$$H_{12}$$O_{6}$ $\xrightarrow[]{enzyme}$ $2C_{2}$$H_{5}$`OH` `+` $2CO_{2}$ 

`(3)` ethanol `->` acetic acid

`PTHH` `:` $C_{2}$$H_{5}$`OH` `+` $O_{2}$ $\xrightarrow[giấm]{men}$ $CH_{3}$`COOH` `+` $H_{2}$`O`

`(4)` acetic acid `->` ethyl acetate

`PTHH` `:` $CH_{3}$`COOH` `+` $C_{2}$$H_{5}$`OH` $\xrightarrow[t_{o}]{H_{2}SO_{4}đ}$ $CH_{3}$`COO`$C_{2}$$H_{5}$ `+` $H_{2}$`O`

`(5)` Glucose `->` Ag

`PTHH` `:` $C_{6}$$H_{12}$$O_{6}$ `+` $Ag_{2}$`O` `->` $\xrightarrow[]{t_{o}}$ $C_{6}$$H_{12}$$O_{7}$ `+` `Ag` `↓`

Cái cuối không rõ câu hỏi, chắc là tính hiệu suất 

$n_{glucose}$ `=` `300/180` `=` `5/3`

Từ `(2)` `=>` $2n_{glucose}$ `=` .$n_{C_{2}H_{5}OH}$$(lt)$ `=` `10/3` `(mol)`

            `=>` $m_{C_{2}H_{5}OH}$$(lt)$ `=` `10/3` `.` `46` `=` `460/3` `(g)`

`=>` `H` `=` `{92.3}/460` `=` `60` `%`

$minhle504$