Đáp án+Giải thích các bước giải:

Câu `5:`

`n_(C_2H_5OH)=(18,4)/46=0,4(mol)`

PTHH: `C_2H_5OH+CH_3COOH` $\buildrel{{H_2SO_4(đ),t^0}}\over\rightleftharpoons$ `CH_3COOC_2H_5+H_2O`

Theo PTHH

`=>n_(CH_3COOC_2H_5)=n_(C_2H_5OH)=0,4(mol)`

`=>m_(CH_3COOC_2H_5)(l t)=0,4*88=35,2(g)`

`=>m_(CH_3COOC_2H_5)(t t)=35,2*80/100=28,16(g)`

Câu `6:`

`n_(CH_3COOH)=12/60=0,2(mol)`

PTHH: `C_2H_5OH+CH_3COOH` $\buildrel{{H_2SO_4(đ),t^0}}\over\rightleftharpoons$ `CH_3COOC_2H_5+H_2O`

Theo PTHH

`=>n_(CH_3COOH)=n_(CH_3COOC_2H_5)=0,2(mol)`

`=>m_(CH_3COOC_2H_5)(l t)=0,2*88=17,6(g)`

`=>m_(CH_3COOC_2H_5)(t t)=17,6*70/100=12,32(g)`

`#DR`