1)

`7x - (2x-1) = 2 (x-5) + 2`

`7x - 2x + 1 = 2x - 10 + 2`

`5x + 1 = 2x - 8`

`5x - 2x = -8 - 1`

`3x = -9`

`x = -3`

Vậy, phương trình có nghiệm `x = -3`

2) `(x+1)/2023 + (x+4)/1010 = (x+5)/2019 + (x+8)/1008`

`[(x+1)/2023 + 1] + [(x+4)/1010 + 2] = [(x+5)/2019 + 1] + [(x+8)/1008 + 2]`

`(x+1+2023)/2023 + (x+4+1010.2)/1010 = (x+5+2019)/2019 + (x+8+1008.2)/1008`

`(x+2024)/2023 + (x+2024)/1010 = (x+2024)/2019 + (x+2024)/1008`

`(x+2024)/2023 + (x+2024)/1010 - (x+2024)/2019 - (x+2024)/1018 = 0`

`(x+2024) (1/2023 + 1/1010 - 1/2019 - 1/1018) = 0`

Vì `1/2023 + 1/1010 - 1/2019 - 1/1018 ne 0` nên `x+2024 =0`

`x = -2024`

Vậy, phương trình có nghiệm `x = -2024`.