Giúp mình bài này với

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`a)` `(x^3*y^2)/(x^3+x^4)`

`=(x^3*y^2)/[x^3*(1+x)]`

`=y^2/(1+x)`

`b)` `(3x-6y)/(10y-5x)`

`=[3(x - 2y)]/[-5(x-2y)]`

`=(-3)/5`

`c)` `(2x^2-5x-3)/(2x^2+11x+5)`

`=[(2x+1)(x-3)]/[(2x+1)(x+5)]`

`=(x-3)/(x+5)`

`d)` `(xy-3y-9x+27)/(3-x)`

`=[y(x-3)-9(x-3)]/[-(x-3)]`

`=[(x-3)(y-9)]/[-(x-3)]`

`=-(y-9)`

`=9-y`

`e)` `(-4x^2+6xy)/(9xy-6x^2)`

`=[2x(3y-2x)]/[3x(3y-2x)]`

`=2/3`

`f)` `[x(x+1)+(x+1)(x-2)]/[x(x-1)(x+1)]`

`=[(x+1)(x+x-2)]/[x(x-1)(x+1)]`

`=[(x+1)(2x-2)]/[x(x-1)(x+1)]`

`=[2(x+1)(x-1)]/[x(x-1)(x+1)]`

`=2/x`

`g)` `(x^2+xy-2xy-2y^2)/(x^2-x-2xy+2y)`

`=[x(x+y)-2y(x+y)]/[x(x-1)-2y(x-1)]`

`=[(x+y)(x-2y)]/[(x-1)(x-2y)]`

`=(x+y)/(x-1)`