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Đáp án:
`a, x/y^2+3/y^2=(x+3)/y^2`
`b, (x+y)/(x^2 y)+(y+7)/(x^2 y)=(x+2y+7)/(x^2 y)`
`c, (x+5)/(x+2)+(2x+1)/(x+2)=(3x+6)/(x+2)=3`
`d, (2x-1)/(x-1)-(x-2)/(x-1)=(x-1)/(x-1)=1`
`e, (x+1)/(x+2) +(x-10)/(x+2)+(x+3)/(x+2)=(3x-6)/(x+2)`
`f, (4x+5)/(x+2)-(2x+1)/(x+2)=(2x+4)/(x+2)=2`
`g, (x^2+4)/(y(y+3))+(6x+5)/(y(y+3))=(x^2+6x+9)/(y(y+3))=(x+3)^2/(y(y+3))`
`h, (5x^2-17)/(4xy-10y)-(x^2+8)/(4xy-10y)=(4x^2-25)/(4xy-10y)=((2x-5)(2x+5))/(2y(2x-5))=(2x+5)/(2y)`
`i, (x^2+2)/(2xy-2y)-(2x+1)/(2y(x-1))=(x^2-2x+1)/(2y(x-1))=(x-1)^2/(2y(x-1))=(x-1)/(2y)`
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Câu 19 :
`a)` `\frac{x}{y^2}` `+` `\frac{3}{y^2}`
`=` `\frac{x+3}{y^2}`
`b)` `\frac{x+y}{x^2y}` `+` `\frac{y+7}{x^2y}`
`=` `\frac{x+y+y+7}{x^2y}`
`=` `\frac{x+2y+7}{x^2y}`
`c)` `\frac{x+5}{x+2}` `+` `\frac{2x+1}{x+2}`
`=` `\frac{x+5+2x+1}{x+2}`
`=` `\frac{3x+6}{x+2}`
`=` `\frac{3.(x+2)}{x+2}`
`=` `3`
`d)` `\frac{2x-1}{x-1}` `-` `\frac{x-2}{x-1}`
`=` `\frac{2x-1-x+2}{x-1}`
`=` `\frac{x+1}{x-1}`
`e)` `\frac{x+1}{x-2}` `+` `\frac{x-10}{x-2}` `+` `\frac{x+3}{x-2}`
`=` `\frac{x+1+x-10+x+3}{x-2}`
`=` `\frac{3x-6}{x-2}``\frac{3.(x-2)}{x-2}`
`=` `3`
`f)` `\frac{4x+5}{x+2}` `-` `\frac{2x+1}{x+2}`
`=` `\frac{4x+5-2x-1}{x+2}`
`=` `\frac{2x+4}{x+2}`
`=` `\frac{2.(x+2)}{x+2}`
`=` `2`
`g)` `\frac{x^2+4}{y.(x+3)}` `+` `\frac{6x+5}{y.(x+3)}`
`=` `\frac{x^2+4+6x+5}{y.(x+3)}`
`=` `\frac{x^2+6x+9}{y.(x+3)}`
`=` `\frac{(x+3)^2}{y.(x+3)}`
`=` `\frac{x+3}{y}`
`h)` `\frac{5x^2-17}{4xy-10y}` `-` `\frac{x^2+8}{4xy-10y}`
`=` `\frac{5x^2-17-x^2-8}{4xy-10y}`
`=` `\frac{4x^2-25}{4xy-10y}`
`=` `\frac{(2x-5).(2x+5)}{2y.(2x-5)}`
`=` `\frac{2x+5}{2y}`
`i)` `\frac{x^2+2}{2xy-2y}` `-` `\frac{2x+1}{2y.(x-1)}`
`=` `\frac{x^2+2-2x-1}{2y.(x-1)}`
`=` `\frac{x^2-2x+1}{2y.(x-1)}`
`=` `\frac{(x-1)^2}{2y.(x-1)}`
`=` `\frac{x-1}{2y}`
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