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$\text{x²(x - 2) = 3x(x - 2)}$

$\text{x²(x - 2) - 3x(x - 2) = 0}$

$\text{(x - 2)(x² - 3x) = 0}$

$\text{x(x - 3)(x - 2) = 0}$

$\text{*TH1: x = 0}$

$\text{*TH2: x - 3 = 0}$

          $\text{x      = 3}$

$\text{*TH3: x - 2 = 0}$

          $\text{x      = 2}$

$\text{Vậy có 3 giá trị x thoả mãn x²(x - 2) = 3x(x - 2)}$