`(x-1)/(x+3)-x/(x-3)=10/(x^2-9)`  `(x ne +-3)`

`((x-1)(x-3))/((x-3)(x+3)) - (x(x+3))/((x-3)(x+3))=10/((x-3)(x+3))`

`x^2 -4x +3 - x^2 -3x =10`

`-7x +3=10`

`-7x=7`

`x=-1 (tmđk)`

Vậy `....`

`d`

`1/(x+2) -2/(x^2-2x+4)=(x-4)/(x^3+8)`   `(x ne -2)`

`(x^2-2x+4)/((x+2)(x^2-2x+4))-(2(x+2))/((x+2)(x^2-2x+4))=(x-4)/((x+2)(x^2-2x+4))`

`x^2-2x+4 -2x -4 = x-4`

`x^2 -5x -x+4=0`

`(x-4)(x-1)=0`

`x-4=0` hoặc `x-1=0`

`x=4(tmđk)` hoặc `x=1 (tmđk)`

Vậy `....`