Giải giúp em vs ạ cảm ơn ạ

$\textbf{Bài 2:}$

`a)`PTHH:

$\rm 3Fe+2O_2\xrightarrow{t^o} Fe_3O_4$

`b)`$\rm n_{Fe_3O_4}=\dfrac{m}{M}=\dfrac{2,32}{232}=0,01(mol)$

Theo pthh $\rm n_{O_2}=2.n_{Fe_3O_4}=2.0,01=0,02(mol)$

$\rm V_{O_2}=24,79.n=24,79.0,02=0,4958(l)$