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`A=\sqrt{5-2\sqrt{6}}-1/(\sqrt{3}+\sqrt{2})+\sqrt{1/4}`

`A=\sqrt{3-2\sqrt{6}+2}-(1(\sqrt{3}-\sqrt{2}))/((\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2}))+1/2`

`A=\sqrt{(\sqrt{3}-\sqrt{2})^2}-(\sqrt{3}-\sqrt{2})/(3-2)+1/2`

`A=|\sqrt{3}-\sqrt{2}|-(\sqrt{3}-\sqrt{2})/1+1/2`

`A=\sqrt{3}-\sqrt{2}-\sqrt{3}+\sqrt{2}+1/2`

`A=1/2`

`B=((\sqrt{x})/(\sqrt{x}-1)-(4\sqrt{x})/(x-1))÷(x-2\sqrt{x})/(x-1)`

`B=[(\sqrt{x})/(\sqrt{x}-1)-(4\sqrt{x})/((\sqrt{x}-1)(\sqrt{x}+1))]·(x-1)/(x-2\sqrt{x})`

`B=(\sqrt{x}(\sqrt{x}+1)-4\sqrt{x})/((\sqrt{x}-1)(\sqrt{x}+1))·(x-1)/(x-2\sqrt{x})`

`B=(x+\sqrt{x}-4\sqrt{x})/(x-1)·(x-1)/(x-2\sqrt{x})`

`B=(x-3\sqrt{x})/(x-1)·(x-1)/(x-2\sqrt{x})`

`B=(\sqrt{x}(\sqrt{x}-3))/(x-1)·(x-1)/(\sqrt{x}(\sqrt{x}-2))`

`B=(\sqrt{x}-3)/(\sqrt{x}-2)`

`b)`

`A=B`

`1/2=(\sqrt{x}-3)/(\sqrt{x}-2)`

`2(\sqrt{x}-3)=1(\sqrt{x}-2)`

`2\sqrt{x}-6=\sqrt{x}-2`

`2\sqrt{x}-\sqrt{x}=-2+6`

`\sqrt{x}=4`

`x=16 (TM)`

Vậy `x=16`