Giúp tôi với mọi người ơi

Đáp án`+`Giải thích các bước giải:

`1,`

`1, x^3 + 1= x^3 + 1^3=  (x + 1)(x^2 -x + 1)`

`2, x^3 + 8 = x^3 + 2^3 = (x+ 2)(x^2 -2x + 4)`

`3, x^3 - 8 = x^3 - 2^3 = (x - 2)(x^2 + 2x + 4)`

`4, x^3 - 27 = x^3 -3^3 = (x - 3)(x^2 +3x + 9)`

`5, x^3 + y^3= (x + y)(x^2 -xy  + y^2)`

`6, x^3 + 8y^3=x^3+ (2y)^3 = (x + 2y)(x^2-  2xy + 4y^2)`

`7, x^3 - y^3 = (x -y)(x^2 + xy + y^2)`

`8,x^3 - 8y^3 = x^3 - (2y)^3= (x - 2y)(x^2 + 2xy + 4y^2)`

`9, 1 + 8x^3 = 1^3 + (2x)^3 = (1 + 2x)(1 - 2x + 4x^2)`

`10, 1 + 27y^3 = 1^3 + (3y)^3 = (1 + 3y)(1 -3y + 9y^2)`

`11, 1 - 8x^3 = 1^3 - (2x)^3 = (1 - 2x)(1 + 2x + 4x^2)`

`12, 27x^3 - 1=  (3x)^3 - 1=  (3x - 1)(9x^2 + 3x + 1)`

`2:`

`1, (x + 1)(x^2 - x + 1) = x^3 + 1`

`2, (x - 1)(x^2 +x + 1) = x^3 - 1`

`3, (x - 2)(x^2 + 2x + 4) = x^3 - 2^3 = x^3 - 8`

`4, (x + 2)(x^2 - 2x + 4) = x^3 + 2^3 = x^3 + 8`

`5, (x - 3)(x^2 +3x + 9) = x^3 - 3^3=  x^3 - 27`

`6, (x - 4)(x^2 + 4x + 16) = x^3 - 4^3 = x^4 - 64`

`7, (x - 5)(x^2 + 5x + 25) = x^3 - 5^3 = x^3 - 125`

`8, (2x + 1)(4x^2 - 2x + 1) = (2x)^3 + 1^3=  8x^3 + 1`

`9, (3x + 2)(3x^2- 6x + 4) = (3x)^3 + 2^3 = 27x^3 + 8`

`10, (x^2 + 3)(x^4 - 3x^2+ 9) = (x^2)^3 + 3^3 = x^6 + 27`

`11, (x^2 + 2)(x^4 - 2x^2 + 4) = (x^2)^3 + 2^3 = x^6 + 8`

`12, (x^3 - 2)(x^6 + 2x^3 + 4) = (x^3)^3 - 2^3=  x^9 - 8`

`***`sharksosad