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Đáp án:
`↓`
Giải thích các bước giải:
`1) x(x-1) +(1-x)^2`
`=x(x-1)+(x-1)^2`
`=(x-1)[x+(x-1)]`
`=(x-1)(x+x-1)`
`=(x-1)(2x-1)`
----------------------
`2) (x+1)^2 -3(x+1)`
`=(x+1)(x+1-3)`
`=(x+1)(x-2)`
----------------------
`3) 2x(x-2)-(x-2)^2`
`=(x-2)[2x-(x-2)]`
`=(x-2)(2x-x+2)`
`=(x-2)(x+2)`
----------------------
`4) 3x(x-1)^2 -(1-x)^3`
`=3x(1-x)^2 -(1-x)^3`
`=(1-x)^2 .[3x-(1-x)]`
`=(1-x)^2 .(3x+x-1)`
`=(4x-1)(1-x)^2`
----------------------
`5) 3x(x+2) -5(x+2)^2`
`=(x+2)[3x-5(x+2)]`
`=(x+2)(3x-5x-10)`
`=(x+2)(-2x-10)`
`=-2(x+2)(x+5)`
----------------------
`6) 4x(x-y)+3(y-x)^2`
`=4x(x-y)+3(x-y)^2`
`=(x-y)[4x+3(x-y)]`
`=(x-y)(4x+3x-3y)`
`=(x-y)(7x-3y)`
Hãy giúp mọi người biết câu trả lời này thế nào?
1
$x(x-1) + (1-x)^2$
$= x(x-1) + (-(x-1))^2$
$= x(x-1) + (x-1)^2$
$= (x-1)(x + (x-1))$
$= (x-1)(2x-1)$
2
$(x+1)^2 - 3(x+1)$
$= (x+1)((x+1) - 3)$
$= (x+1)(x - 2)$
3)
$2x(x-2) - (x-2)^2$
$= (x-2)(2x - (x-2))$
$= (x-2)(2x - x + 2)$
$= (x-2)(x+2)$
4
$3x(x-1)^2 - (1-x)^3$
$= 3x(x-1)^2 - (-(x-1))^3$
$= 3x(x-1)^2 + (x-1)^3$
$= (x-1)^2(3x + (x-1))$
$= (x-1)^2(3x + x - 1)$
$= (x-1)^2(4x - 1)$
5
$3x(x+2) - 5(x+2)^2$
$= (x+2)(3x - 5(x+2))$
$= (x+2)(3x - 5x - 10)$
$= (x+2)(-2x - 10)$
$= -2(x+2)(x+5)$
6
$4x(x-y) + 3(y-x)^2$
$= 4x(x-y) + 3(-(x-y))^2$
$= 4x(x-y) + 3(x-y)^2$
$= (x-y)(4x + 3(x-y))$
$= (x-y)(4x + 3x - 3y)$
$= (x-y)(7x - 3y)$
Hãy giúp mọi người biết câu trả lời này thế nào?
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