Giải giúp t cách trình bày rõ ràng ra như câu1 nha ( kh bt câu1 lm đúng ko nx)

1

$\left(\dfrac{8}{3}\right)^8 \cdot \left(\dfrac{9}{4}\right)^8 = \left(\dfrac{8}{3} \cdot \dfrac{9}{4}\right)^8 = \left(\dfrac{8 \cdot 9}{3 \cdot 4}\right)^8 = \left(\dfrac{72}{12}\right)^8 = 6^8$

2

$\left(\dfrac{3}{7}\right)^{12} \cdot \left(\dfrac{21}{5}\right)^{12} = \left(\dfrac{3}{7} \cdot \dfrac{21}{5}\right)^{12} = \left(\dfrac{3 \cdot 21}{7 \cdot 5}\right)^{12} = \left(\dfrac{63}{35}\right)^{12} = \left(\dfrac{9}{5}\right)^{12}$

3

$\left(\dfrac{-4}{13}\right)^5 \cdot \left(\dfrac{26}{5}\right)^5 = \left(\dfrac{-4}{13} \cdot \dfrac{26}{5}\right)^5 = \left(\dfrac{-4 \cdot 26}{13 \cdot 5}\right)^5 = \left(\dfrac{-104}{65}\right)^5 = \left(\dfrac{-8}{5}\right)^5$

4

$\left(\dfrac{12}{7}\right)^4 \cdot \left(\dfrac{35}{16}\right)^4 = \left(\dfrac{12}{7} \cdot \dfrac{35}{16}\right)^4 = \left(\dfrac{12 \cdot 35}{7 \cdot 16}\right)^4 = \left(\dfrac{420}{112}\right)^4 = \left(\dfrac{15}{4}\right)^4$

5

$\left(\dfrac{6}{7}\right)^{13} \cdot \left(\dfrac{49}{18}\right)^{13} = \left(\dfrac{6}{7} \cdot \dfrac{49}{18}\right)^{13} = \left(\dfrac{6 \cdot 49}{7 \cdot 18}\right)^{13} = \left(\dfrac{294}{126}\right)^{13} = \left(\dfrac{7}{3}\right)^{13}$

6,

$\left(\dfrac{-1}{4}\right)^{12} : \left(\dfrac{13}{12}\right)^{12} = \left(\dfrac{-1}{4} : \dfrac{13}{12}\right)^{12} = \left(\dfrac{-1}{4} \cdot \dfrac{12}{13}\right)^{12} = \left(\dfrac{-1 \cdot 12}{4 \cdot 13}\right)^{12} = \left(\dfrac{-12}{52}\right)^{12} = \left(\dfrac{-3}{13}\right)^{12}$

7

$\left(\dfrac{-10}{3}\right)^4 : \left(\dfrac{-5}{6}\right)^4 = \left(\dfrac{-10}{3} : \dfrac{-5}{6}\right)^4 = \left(\dfrac{-10}{3} \cdot \dfrac{6}{-5}\right)^4 = \left(\dfrac{-10 \cdot 6}{3 \cdot (-5)}\right)^4 = \left(\dfrac{-60}{-15}\right)^4 = 4^4 = 256$

8

$\left(\dfrac{4}{7}\right)^{19} : \left(\dfrac{-12}{35}\right)^{19} = \left(\dfrac{4}{7} : \dfrac{-12}{35}\right)^{19} = \left(\dfrac{4}{7} \cdot \dfrac{35}{-12}\right)^{19} = \left(\dfrac{4 \cdot 35}{7 \cdot (-12)}\right)^{19} = \left(\dfrac{140}{-84}\right)^{19} = \left(\dfrac{-5}{3}\right)^{19}$

9)

$\left(\dfrac{-4}{7}\right)^{11} : \left(\dfrac{16}{-28}\right)^{11} = \left(\dfrac{-4}{7} : \dfrac{16}{-28}\right)^{11} = \left(\dfrac{-4}{7} \cdot \dfrac{-28}{16}\right)^{11} = \left(\dfrac{-4 \cdot (-28)}{7 \cdot 16}\right)^{11} = \left(\dfrac{112}{112}\right)^{11} = 1^{11} = 1$