Giải giúp mình hai bài này

`#0409`

`11,`

`(x-1)^2+4x-4=0`

`(x-1)^2+4(x-1)=0`

`(x-1+4)(x-1)=0`

`(x+3)(x-1)=0`

`th_1 : x+3=0`

`x=-3`

`tth_2 : x-1=0`

`x=1`

Vậy `S={-3;1}`

`13,`

`(2-3x)(x+11)=(3x-2)(2-5x)`

`(2-3x)(x+11)-(3x-2)(2-5x)=0`

`(2-3x)(x+11)+(2-3x)(2-5x)=0`

`(2-3x)(x+11+2-5x)=0`

`(2-3x)(-4x+13)=0`

`th_1 : 2-3x=0`

`3x=2`

`x=2/3`

`th_2 : -4x+13=0`

`-4x=-13`

`x=13/4`

Vậy `S={2/3;13/4}`