`vec(AC)=(-5;0;2)=>AC:{(x=7-5t),(y=3),(z=3+2t):}`

`H in AC=>H(7-5t ; 3;3+2t)`

Ta có: `vec(BH)=(6-5t;1;-1+2t)`

Vì `BH bot AC=>vec(BH)*vec(AC)=0`

`<=>` `(6-5t)*(-5)+1*0+(-1+2t)*2=0`

`<=>` `t=32/29`

`=>` `H(43/29; 3; 151/29)`

`=>` `{(x=43/29),(y=3),(z=151/29):}`

`=>` `58(x+y+z)=58(43/29+3+151/29)=562`