

a)(1/3)^x+3+(1/3)^x+2=4/27
b)(2/3)^x+2+(2/3)^x+1=20/27
c) (3x-2)^2=49/81
d) (1-5x)^3=1/27
( Giúp e vs ạ)
Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
`a.`
`(1/3)^(x+3) + (1/3)^(x+2) = 4/27`
`(1/3)^x . (1/3)^3 + (1/3)^x . (1/3)^2= 4/27`
`(1/3)^x . ( 1/27 + 1/9) = 4/27`
`(1/3)^x . 4/27 = 4/27`
`(1/3)^x =1`
`(1/3)^x= (1/3)^0`
`x=0`
Vậy `x=0`
`b.`
`(2/3)^(x+2) + (2/3)^(x+1) = 20/27`
`(2/3)^x . (2/3)^2 + (2/3)^x . 2/3 = 20/27`
`(2/3)^x . ( 4/9 + 2/3) =20/27`
`(2/3)^x . 10/9 = 20/27`
`(2/3)^x = 2/3`
`(2/3)^x = (2/3)^1`
`x=1`
Vậy `x=1`
`c.`
`(3x-2)^2 = 49/81`
`(3x-2)^2 = ( +-7/9)^2`
`TH1 :`
`3x-2 = 7/9`
`3x = 7/9 + 2`
`3x = 7/9 + 18/9`
`3x = 25/9`
`x = 25/27`
`TH2 :`
`3x-2 = -7/9`
`3x = -7/9 + 2`
`3x = -7/9 + 18/9`
`3x =11/9`
`x=11/27`
Vậy `x in { 25/27;11/27}`
`d.`
`(1-5x)^3 = 1/27`
`(1-5x)^3 = (1/3)^3`
`1-5x = 1/3`
`5x = 2/3`
`x = 2/15`
Vậy `x=2/15`
Hãy giúp mọi người biết câu trả lời này thế nào?
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Đáp án + Giải thích các bước giải:
`a. \frac{1}{3}^{x + 3}+ \frac{1}{3}^{x + 2} = 4/27`
`\frac{1}{3}^{x + 2} . (1/3)^1 + \frac{1}{3}^{x + 2} = 4/27`
`\frac{1}{3}^{x + 2}. (1/3 + 1) = 4/27`
`\frac{1}{3}^{x} . 4/3 = 4/27`
`\frac{1}{3}^{x} = 4/27 : 4/3`
`\frac{1}{3}^{x} = 1/9`
`\frac{1}{3}^{x} = (1/3)^2`
`x = 2`
`Vậy x = 2`
`b. \frac{2}{3}^{x + 2}+ \frac{2}{3}^{x + 1} = 20/27`
`\frac{2}{3}^{x} . (2/3)^2 + \frac{2}{3}^{x} . 2/3= 20/27`
`\frac{2}{3}^{x} . 4/9 + \frac{2}{3}^{x} . 2/3= 20/27`
`\frac{2}{3}^{x}. (4/9 + 2/3) = 20/27`
`\frac{2}{3}^{x} . 10/9 = 20/27`
`\frac{2}{3}^{x} = 20/27 : 10/9`
`\frac{2}{3}^{x} = 2/3`
`\frac{2}{3}^{x} = (2/3)^1`
`x = 1`
`Vậy x = 1`
`c. (3x - 2)^2 = 49/81`
`(3x - 2)^2 = (7/9)^2 hoặc (3x - 2)^2 = (-7/9)^2`
`3x - 2 = 7/9 3x - 2 = -7/9`
`3x = 7/9 + 2 3x = -7/9 + 2`
`3x = 25/9 3x = 11/9`
`x = 25/9 : 3 x = 11/9 : 3`
`x = 25/27 x = 11/27`
`Vậy x ∈ {25/27;11/27}`
`d. (1 - 5x)^3 = 1/27`
`(1 - 5x)^3 = (1/3)^3`
`1 - 5x = 1/3`
`5x = 1 - 1/3`
`5x = 2/3`
`x = 2/3 : 5`
`x = 2/15`
`Vậy x = 2/15`
Hãy giúp mọi người biết câu trả lời này thế nào?
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