`color{#fc88d2}{} color{#fc88d2}{t} color{#fc88d2}{t} color{#fc88d2}{h} color{#fc88d2}{u} color{#fc88d2}{y} color{#6d79fc}{} color{#8892fc}{} color{#fc88d2}{}`

`(x-1/3)^2-1/2=1` `3/4`

`(x-1/3)^2=7/4+1/2`

`(x-1/3)^2=9/4`

`(x-1/3)=3/2 hoặc (-3)/2`

`TH1 : x-1/3=3/2`

                `x=3/2+1/3`

                `x=11/6`

`TH2 : x-1/3=(-3)/2`

                `x=(-3)/2+1/3`

                `x=-7/6`

Vậy `x∈{11/6;(-7)/6}`