

Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
`a)x^2-4x+4`
`=x^2-2*x*2+2^2`
`=(x-2)^2`
`b)x^2-6x+9`
`=x^2-2*x*3+3^2`
`=(x-3)^2`
`c)x^2+25+10x`
`=x^2+10x+25`
`=x^2+2*x*5+5^2`
`=(x+5)^2`
`d)x^2-1/4y^2`
`=x^2-(1/2y)^2`
`=(x-1/2y)(x+1/2y)`
`e)x^3+3x^2+3x+1`
`=x^3+3*x^2*1+3*x*1^2+1^3`
`=(x+1)^3`
`f)x^3-6x^2+12x-8`
`=x^3-3*x^2*2+3*x*2^2-2^3`
`=(x-2)^3`
`g)8x^3+12x^2+6x+1`
`=(2x)^3+3*(2x)^2*1+3*2x*1^2+1^3`
`=(2x+1)^3`
`h)x^3-3/2x^2+3/4x-1/8`
`=x^3-3*x^2*1/2+3*x*(1/2)^2-(1/2)^3`
`=(x-1/2)^3`
`i)x^3-9x^2+27x-27`
`=x^3-3*x^2*3+3*x*3^2-3^3`
`=(x-3)^3`
`k)27x^3+27x^2+9x+1`
`=(3x)^2+3*(3x)^2*1+3*3x*1^2+1^3`
`=(3x+1)^3`
`m)x^3-x^2+1/3x-1/27`
`=x^3-3*x^2*1/3+3*x*(1/3)^2-(1/3)^3`
`=(x-1/3)^3`
`n)4x^2+1-4x`
`=(2x)^2-2*2x*1+1^2`
`=(2x-1)^2`
`o)9x^2-4`
`=(3x)^2-2^2`
`=(3x+2)(3x-2)`
`p)1/4x^2-25`
`=(1/2x)^2-5^2`
`=(1/2x+5)(1/2x-5)`
`q)1/4x^2-9y^2`
`=(1/2x)^2-(3y)^2`
`=(1/2x-3y)(1/2x+3y)`
`r)x^2-(2x+1)^2`
`=(x-2x-1)(x+2x+1)`
`=(-1-x)(3x+1)`
Hãy giúp mọi người biết câu trả lời này thế nào?
![]()
`a.x^2-4x+4``
`=x^2-2*2*x+2^2`
`=(x-2)^2`
`b.x^2-6x+9`
`=x^2-2*3*x+3^2`
`=(x-3)^2`
`c.x^2+25+10x`
`=x^2+2*5*x+5^2`
`=(x+5)^2`
`d.x^2-1/4y^2`
`=(x-1/2y)(x+1/2y)`
`e.x^3+3x^2+3x+1`
`=x^3+3x^2*1+3*1^2*x+1^3`
`=(x+1)^3`
`f.x^3-6x^2+12x-8`
`=x^3-3*x^2*2+3*2^2*x-2^3`
`=(x-2)^3`
`g.8x^3+12x+6x+1`
`=(2x)^3+3*(2x)^2*1+3*1^2*(2x)+1^3`
`=(2x+1)^3`
`h.x^3-3/2x^2+3/4x-1/8`
`=x^3-3*x^2*1/2+3*(1/2)^2*x-(1/2)^3`
`=(x-1/2)^3`
`i.x^3-9x^2+27x-27`
`=x^3-3*x^2*3+3*3^2*x-3^3`
`=(x-3)^3`
`l.27x^3+27x^2+9x+1`
`=(3x)^3+3*(3x)^2*1+3*3x*1^2+1^3`
`=(3x+1)^3`
`m.x^3-x^2+1/3x-1/27`
`=x^3-3*1/3*x^2+3*(1/3)^2*x-(1/3)^3`
`=(x-1/3)^3`
`n.4x^2+1-4x`
`=(2x)^2-2*2x*1+1^2`
`=(2x-1)^2`
`o.9x^2-4`
`=(3x-2)(3x+2)`
`p.1/4x^2-25`
`=(1/2x-5)(1/2x+5)`
`q.1/4x^2-9y^2`
`=(1/2x-3y)(1/2x+3y)`
`r.x^2-(2x+1)^2`
`=(x-2x-1)(x+2x+1)`
`=(-1-x)*(3x+1)`
Hãy giúp mọi người biết câu trả lời này thế nào?
Bảng tin