`\color{pink}{#Bơ}`

Xét tam giác vuông `ABC`, có:

        `AC = 8`

        `\hat{ACB} = 54^o`

`=> sin(\hat C) = (AB)/(AC) => AB . sin(54^o) = 8 . sin(54^o) ~~ 6,47`

Ta có:

`sin(\hat{ACH}) = (AH)/(AC) => AH = AC . sin(74^o) = 8 . sin(74^o) = 7,69m`

`sin(\hat D) = (AH)/(AD) = (7,69)/(9,6) ~~ 0,801`

`=> \hat{ADC} = arcsin(0,801) = 53,22^o`

 `\color{#1AD5F7}{꧁⋆⟡T}\color{#1AD5F7}{D}\color{#4DA6E6}{u}\color{#668EDD}{n}\color{#8077D5}{g}\color{#995FCD}{G}\color{#EA2F90}{M⟡⋆꧂}`