`a) (2x+3)/(5x-3) - 3/(4x-6) = 2/5`

ĐKXĐ: `x ne 3/5; x ne 3/2`

`=> (2x+3)/(5x-3) - 3/(2(2x-3)) = 2/5`

`=> 10(4x^2 - 9) - 75x + 45 = 4(10x^2 - 21x + 9)`

`=> 40x^2 - 90 - 75x + 45 = 40x^2 - 84x + 36`

`=> 40x^2 - 75x - 45 = 40x^2 - 84x + 36`

`=> -75x - 45 = -84x + 36`

`=> 9x = 81`

`=> x = 9` (thỏa mãn)

Vậy `x = 9`

``

`b) x + 1/x = 2`

ĐKXĐ: `x ne 0`

`=> (x^2+1)/x = (2x)/x`

`=> x^2 + 1 = 2x`

`=> x^2 - 2x + 1 = 0`

`=> (x-1)^2 = 0`

`=> x - 1 = 0`

`=> x = 1` (thỏa mãn) 

Vậy `x = 1`